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n3w2sql avatar image
n3w2sql asked

CASE not giving the required result

My CASE statemtents are giving the wrong result, I am trying to show what is ontime and what is late. I am trying to say when incept <=5 OR madelive <=10 then make it ontime but it is showing as ontime when it should show late. madelive is 9 incept is 7 which should make the policy show as late but shows as ontime(1). my code is below if anyone can help please. CASE WHEN incept sql-server-2008case-statement
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Fatherjack avatar image
Fatherjack answered
That is what you would expect. madelive is less than 10 so the CASE statement is returning 1. Do you need to change the OR to an AND?
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n3w2sql avatar image n3w2sql commented ·
If I changed my statement to AND it would make Ontime and Late both show as 0 would I need to do an AND and an OR to get it to work? Thanks
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Fatherjack avatar image Fatherjack ♦♦ commented ·
Late? Is that another part of your code? Can you edit the question and add the whole statement, with some sample data and what you want the results to show please?
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n3w2sql avatar image n3w2sql commented ·
Sorry for the confuison. CASE WHEN incept >=6 OR madelive >=11 THEN 1 ELSE 0 END AS Late, CASE WHEN incept
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Fatherjack avatar image Fatherjack ♦♦ commented ·
No problem, glad we got it sorted :)
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