Compare Records when item=item and cost!=cost

I query table from DB2 there are six fields I want tot match item to the previous record and if the cost field is differetn then in is added to the temp table

What is the best way to do this in SQL SERVER 2008 R2?

 date           co    loc   po      item    cost
 11/11/11       A     1     1234    XYZ     1.01
 11/11/11       A     1     1234    XYZ     1.08  
 11/11/11       A     1     1234    ABC     5.05
 -- first two same items do not match on cost
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asked Nov 15, 2011 at 11:15 AM in Default

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@jaymz69 Which non-matching record do you need to add to the temp table (first or second)? What about if there are 3 records for the same date, co, loc, po and item?

Nov 15, 2011 at 12:17 PM Oleg

I would take any records when the cost != cost

Nov 15, 2011 at 12:39 PM jaymz69

@jaymz69 Please let me know what do you consider "same item"? Is it just the item column or something else is involved?

Nov 15, 2011 at 12:44 PM Oleg
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1 answer: sort voted first

There are many ways to get the results you need. In case if you simply need to reveal all records for the same item which don't have the same cost then you can simply group by whatever column make up the item and then include only those which have different prices (those will obviously have minimum and maximum of the price different), for example:

     a.date, a.co, a.loc, a.po, a.item, a.cost
     from YourTable a inner join
             from YourTable
             group by item
             having min(price) <> max(price)
     ) b 
         on a.item = b.item;

Hope this helps,


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answered Nov 15, 2011 at 12:52 PM

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asked: Nov 15, 2011 at 11:15 AM

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Last Updated: Nov 15, 2011 at 12:14 PM

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