how to collect first row values into the second row

I am using sql2005 how to collect the first row values without using lead funtion

what is equal to lead funtion in sql server 2005
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asked Mar 14, 2012 at 06:01 PM in Default

jkchowdary gravatar image

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1 answer: sort voted first

Mr. Riley had an excellent answer to that in a similar question [here][1].

[1]: http://ask.sqlservercentral.com/questions/2623/coalesce-multiple-rows-into-a-comma-delimited-valu.html
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answered Mar 14, 2012 at 08:15 PM

Mark gravatar image

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I think the OP's question was to find the previous rows values e.g. running total.
Mar 15, 2012 at 06:51 AM Usman Butt
Ha! I think you're right. Obviously, I am not an Oracle developer.
Mar 15, 2012 at 02:04 PM Mark
BTW, Lead function is now available with SQL Server 2012 :)
Mar 15, 2012 at 02:15 PM Usman Butt

There was a similar question in the past here. @WilliamDurkin answered using recursive CTE and I posted an answer using the quirky update which is a very fast method of calculating the running totals. Of course in SQL Server 2012 both LEAD and LAG are available as @Usman already mentioned, but in earlier versions the quirky update is a very good method to use. Here is the link:


Additionally, there is an excellent article by Jeff Moden titled [Solving the Running Total and Ordinal Rank Problems (Rewritten)][2]. Please read it.

There is another very simple way, which consists of including the row_number() into select (partitioned on per account basis) and then it is possible to left join the result with itself on the "off-by-one" basis to have the values from the previous row available to the current row. This method is not as fast as quirky update but works well with record counts in 6 digits or less.


[2]: http://www.sqlservercentral.com/articles/T-SQL/68467/
Mar 15, 2012 at 02:45 PM Oleg
The same question I mentioned earlier also has a very good answer by @Pavel Pawlowski which uses the CLR function and it is also smoking fast.
Mar 15, 2012 at 02:56 PM Oleg
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asked: Mar 14, 2012 at 06:01 PM

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Last Updated: Mar 15, 2012 at 02:56 PM