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Drop index .......with (Move To [Data Partition Scheme] (.....))

I hope there is only one method to create partition on nonempty table (pls share any there is any other method for same) :

Drop index .......with (Move To [Data Partition Scheme] (.....))

Does this commond drop the actual index? if yes, can i create similar index on the table?

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asked Feb 22 '10 at 07:51 AM in Default

kardile gravatar image

kardile
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That command doesn't create a partition - it would remove any partitions created by the index being dropped. To create a partition (or, more accurately, an index over a series of partitons) you would use CREATE INDEX and specify a partition scheme as the destination data space:

CREATE INDEX [myPartitionedIndex]
ON [myTable] ([column])
ON [myPartitionScheme] ([partitoning_column])

In answer to your other questions, yes - the index is actually dropped and yes, you can then create a similar index.

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answered Feb 22 '10 at 08:05 AM

Matt Whitfield gravatar image

Matt Whitfield ♦♦
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Thanks Matt,

what is a difference between
CREATE TABLE......on [myPartitionScheme] ([partitoning_column] and CREATE INDEX......on [myPartitionScheme] ([partitoning_column] ? Which one is preferred & why?
Feb 22 '10 at 10:01 AM kardile
When you specify ON in CREATE TABLE, it's either specifying where the heap goes (if you don't specify a clustered constraint) or it's actually doing nothing at all (if you do specify a clustered constraint). When you specify it on create index, you're specifying where that index will be stored, whether clustered or not.
Feb 22 '10 at 10:46 AM Matt Whitfield ♦♦
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asked: Feb 22 '10 at 07:51 AM

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Last Updated: Feb 22 '10 at 08:25 AM