Hi, I have a varchar column. The values are separated using a comma (,). For example, the column values are as follows:
I would like to extract the last value from each column. With respect to the above example, the output should be as follows:
I know that we should use substring function to do this, but I am not sure how I can find out the value after '' in the reverse direction. Thanks in advance.
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I found the solution for this problem. I used Substr and Instr functions. If we specificy position of occurrance of '' as 1, the instr function will calculate the position in reverse direction.
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select substr('P1101Part1This is a part',instr('P1101Part1This is a part','',1)+1) from dual
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use regular expressions in oracle 10g and above .. here's the example with temp as ( select 'P1101Part1This is a part' STR from dual UNION ALL select 'P2101Part2This is a part number 2' STR from dual UNION ALL select 'P3101Part1.1This is a sub part for part 1' STR from dual ) SELECT regexp_substr(str,'[^]+$',1,1) STR from temp
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use substr/instr functions for all versions of oracle.. here's the example with temp as ( select 'P1101Part1This is a part' STR from dual UNION ALL select 'P2101Part2This is a part number 2' STR from dual UNION ALL select 'P3101Part1.1This is a sub part for part 1' STR from dual ) select substr(str, instr(str, '', 1, 1)+1 ) STR from temp
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