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Date Function

Hi

I have 2 paramater as startdate and enddate After subtracting this ie @date = ( startdate- enddate) Now i want to conert it into @date=@date/60/60/24/365.

It say me datetime cannot be converted into int.

Kindly help me wiyth script
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asked Dec 07 '10 at 06:50 PM in Default

chana gravatar image

chana
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It appears that you are looking for a difference in seconds between 2 dates. If this is so then you don't really need to divide the difference by /60/60/24/365. The difference between 2 datetime values is still a datetime, you cannot divide it by an integer. To get what you need, use datediff function instead:

declare @startdate datetime;
declare @enddate datetime;
declare @result int;

-- populate your parameters (start@date - an hour ago, @enddate - now)
select 
    @enddate = getDate(), 
    @startdate = dateadd(hour, -1, @enddate),
    @result = datediff(second, @startdate, @enddate);

-- now select your result, it will be equal to 3600 :)
select @result;

You can read the [answer to this question][1], it has a pretty detailed explanation about datetime math.

Oleg

[1]: http://ask.sqlservercentral.com/questions/16420/php-with-mssql-strtotime-with-mssql-datetime-column
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answered Dec 07 '10 at 07:53 PM

Oleg gravatar image

Oleg
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asked: Dec 07 '10 at 06:50 PM

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Last Updated: Dec 07 '10 at 10:18 PM