declare @d decimal set @d='2.2875' select round(@d,0)
i need to round it to 2.29...
Nov 10, 2010 at 12:00 AM
Nov 10, 2010 at 01:20 AM
There's 2 issues here:
you haven't defined the decimal with any precision, so by default is defined as decimal(18,0). When you asign 2.2875 to it, it essentially rounds it, giving 2
the second parameter of the round function is the number of decimal places to round to.
so your code needs to be
declare @d decimal (8,2) --for example
Nov 10, 2010 at 12:16 AM
Kev Riley ♦♦
Nov 10, 2010 at 12:17 AM
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asked: Nov 10, 2010 at 12:00 AM
Seen: 665 times
Last Updated: Nov 10, 2010 at 01:20 AM
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