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Sorting data having greater than and lesser than signs

I have data in my table something like this <-3 <-2 <-1 0 1 2 3 >3 >4 11,12,6,9,-4,-6,-9, <-7 etc

so what i want is a query that will give me the result some thing like this

-9,<-7,-6,-4, <-3 <-2 <-1 0 1 2 3,>3,>4,6,9,11,12...

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asked Feb 10, 2010 at 11:51 AM in Default

whiTeWhistlE gravatar image

whiTeWhistlE
1 1 1 1

can you reformat your question, i can't tell which is the column which is the row. It will be even better if you can post the table DDL and sample data in terms of INSERT INTO ....
Feb 10, 2010 at 12:03 PM Squirrel 1
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1 answer: sort voted first

Something like this should work:

use tempdb            
go            
declare @vals table (val varchar(100))            
            
insert @vals            
values ('>-1')            
            
insert @vals            
values ('<-3')            
            
insert @vals            
values ('<3')            
            
insert @vals            
values ('>1')            
            
select val, replace(replace(val, '<', ''), '>', '')            
from @vals            
order by CAST(replace(replace(val, '<', ''), '>', '') AS INT)            

You can use the REPLACE function to strip out the greater than and less than signs and then convert to an integer.

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answered Feb 11, 2010 at 12:20 PM

graz gravatar image

graz ♦
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asked: Feb 10, 2010 at 11:51 AM

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Last Updated: Feb 10, 2010 at 11:51 AM